an airplane from rest accelerates on a runway at 6.50 m/s(square) for 10.25 s. until it finally takes off the ground. what is the distance covered before takeoff?
Given: a = 6.50 m/s(squared) t = 10.25 s vi = 0 m/s Find: d =? d = vit + ½ at(squared) d = (0 m/s)(10.25 s)+ ½ (6.50 m/s2)(10.25 s)(square) d = 341.45m
