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Answered

A man left his house at 10: 15a. m. and reached a town 30km away at 10: 55 a. m. . What was his average speed for the journey?

Sagot :

distance = 30 km            time = 40 mins. 
speed = [tex] \frac{d}{t} [/tex] 
[tex]speed= \frac{30km}{40mins.} = 0.75km/min[/tex]
Put the given first:
distance: 30km
Time: 10:55-10:15 = 10:40 or 10 hrs. and 40 minutes
FORMULA:
v=d/t
v= 30km/10 and 40 hrs.
v= .75 km/hr