Prudence09viz
Answered

Two drivers began their journey with the same amount of petrol in their cars at the same time. The only difference is that the first driver’s car could drive 4 hours in that amount of petrol and the second one could drive 5 hours.
However, they only drove for some time and found that the amount of petrol that was left in one of the cars was four times the petrol left in the other one.

For how long had they driven at this point in time?

I will report nonsense answers

Sagot :

IreneIQviz

Answer:

3.75 hours

Explanation:

While you can solve it as you like, a simple mathematical equation can be used to find out.

Let M be the amount of petrol initially.

Let N be the time for which they drove.

According to the question, the amount of petrol used by first car in N hours = MN / 4

The amount of petrol used by second car in N hours = MN / 5

Hence, the amount of petrol left in the first car = (M - MN / 4)

The amount of petrol left in the second car = (M - MN / 5)

AS per the details given in the question, we can form the below equation:

M - MN / 5 = 4(M - MN / 4)

N = 15 / 4 or 3.75 hours.

Hence, both the drivers have driven the car for 3.75 hours at that particular time.

Step-by-step explanation:

Asyria88viz

Answer:

3.75 hours

Explanation:

While you can solve it as you like, a simple mathematical equation can be used to find out.

Let M be the amount of petrol initially.

Let N be the time for which they drove.

According to the question, the amount of petrol used by first car in N hours = MN / 4

The amount of petrol used by second car in N hours = MN / 5

Hence, the amount of petrol left in the first car = (M - MN / 4)

The amount of petrol left in the second car = (M - MN / 5)

AS per the details given in the question, we can form the below equation:

M - MN / 5 = 4(M - MN / 4)

N = 15 / 4 or 3.75 hours.

Hence, both the drivers have driven the car for 3.75 hours at that particular time.

Step-by-step explanation:

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