Use this problem to answer question #'s 2 & 3.

Jan stands 926 meters from a point directly below the peak of a mountain. The angle of elevation to the top of the mountain is 42°

(Use: sin 42° = 0.67; cos 42° = 0.74; tan 42° = 0.9)

2. Which equation can be used to find the height of the mountain (x)?

a. \: sin \: 42 \: \frac{x}{926}a.sin42 926 x ​

b. \: tan \: 42 \: = \frac{x}{926}b.tan42= 926 x ​

c. \: cos \: 48 \: = \: \frac{926}{x}c.cos48= x 926 ​

d. \: tan \: 42 \: = \frac{x}{926}d.tan42= 926 x ​


3. What is the height of the mountain?
A. 619.6 m
B. 1,028.4 m
C. 833.4 m
D. 1,383.9 m ​