Answered

You have two wires of lengths 12 and 16m. What is the largest
possible integral length of the third side of a triangle you can form using the wires?

Sagot :

X18z0iviz

Answer:

4m

Explanation:

Maximum length of each piece = H.C.F. of 16 m and 20 m.

16=2×2×2×2.

20=2×2×5.

H.C.F. of 16 and 20 = 2×2 = 4 m.

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