Answered

Determine the acceleration of a jeepney which has an initial velocity of 30 km/hr to 68 km/hr in 2hours.

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Answer:

A=19m/s²

Explanation:

[tex]A=\frac{v-v_{0} }{t} \\A=\frac{68-30}{2}\\A=\frac{38}{2} \\A=19[/tex]

a = acceleration

v = final velocity

v0 =  initial velocity

t = time