Dnelskieviz
Answered

Log of 8 to the base 2 + log of 16 to the base 2

Sagot :

[tex] log_{8}(2) = \frac{1}{3} [/tex]

[tex]log _{16} (2) = \frac{1}{4} [/tex]

¹/₃ + ¹/₄ = ⁴/₁₂ + ³/₁₂  (LCD: 12)

= 7/12

The answer is 7/12.