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1. 180(n-2) = 1260
n-2 = 7
n=9
Each interior angle is 1260/9 = 140°.
The sum of the interior angle and its corresponding exterior angle is 180°.
Each exterior angle must be 180°- 140° = 40°.
2. The sum of the interior angles, in degrees, of a regular polygon is given by the formula 180(n – 2), where n is the number of sides. The problem concerns a polygon with twelve sides, so we will let n = 12. The sum of the interior angles in this polygon would be 180(12 – 2) = 180(10) = 1800.
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