Sagot :
Answer:
There are total (2 + 3 + 5) = 10 cubes.
Cubes of same colour are not distinct.
So, total number of possible linear arrangements involving all of them = (10!) / {(2!) * (3!) * (5!)} = 2520
Answer:
There are total (2 + 3 + 5) = 10 cubes.
Cubes of same colour are not distinct.
So, total number of possible linear arrangements involving all of them = (10!) / {(2!) * (3!) * (5!)} = 2520