Answer:
REMEMBER THE "SOHCAHTOA"
Sine – Opposite / Hypotenuse
Cosine – Adjacent / Hypotenuse
Tangent – Opposite / Adjacent
1.
Given – 35 degrees, hypotenuse = 20, adjacent = a
We are going to solve for cosine.
35 = [tex]\frac{a}{20}[/tex] >> a = cos(35) * 20 = 16.3830
a = 16.3830
2.
Given – 32 degrees, hypotenuse = 25, opposite = b
We are going to solve for sine.
32 = [tex]\frac{b}{25}[/tex] >> b = sin(32) * 25 = 13.2480
b = 13.2480
3.
Given – 55 degrees, opposite = 25, adjacent = b
We are going to solve for tangent.
55 = [tex]\frac{25}{b}[/tex] >> 25 = tan(55) * b = b tan(55)
