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Find the height of a vertical pole which casts a shadow 70ft. long on the level ground when the angle of elevation of sun makes an angle of 40 degrees with the horizontal

with solution thank you^^

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LinQiunanOfficial17viz

Shadow on level ground from the angle to the foot of the pole = 20 meter

Height of the pole (opposite the angle) = x

tan θ = tan 60°

Equation:

tan θ = \frac{opposite}{adjacent}

adjacent

opposite

tan 60 = \frac{x}{20}

20

x

x = tan 60 (20)

x = (1.732) (20)

x ≈ 34.64 or 35 meters

ANSWER: The height of vertical pole is 34.64 meters or 35 meters.

Dagsilbviz

Let: x = height of the vertical pole

Solution:

tan∅= x/70

tan40 = x/70

x = 70tan40°

x = 58.74 ft

The height of the pole is 58.74 ft

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