in arithmetic sequence 5,7,9,11, . . . find α21 and s10

Sagot :

To find the nth terms, the formula is

[tex]a_n = a_1 + d(n-1)[/tex]

The common difference in this sequence is 2, so d=2
The first term is 5, so a₁=5

Thus,

[tex]a_{21} = 5 + 2(21-1)=5+40=\boxed{45}[/tex]

[tex]a_{10} = 5 + 2(10-1)=5+18=\boxed{23}[/tex]