[tex]Given: \\ \\ a=? \\ b=16 \\ c=20 \\ \\ Note; \\ The\ given\ triangle\ is\ a\ right\ triangle. \\ \\ Where\ a\ is\ the\ height\ or\ adjacent\ side,\ b\ as\ the\ base\ or\ opposite \\ side\ c\ as\ the\ hypotenuse.\\ \\ Solution: \\ \\ a^2\ +\ b^2=c^2 \\ \\ a^2\ +\ (16)^2=20^2 \\ \\ a^2=20^2-16^2 \\ \\ a^2=400\ -\ 256 \\ \\ a^2=144 \\ \\ \sqrt{a^2}= \sqrt{144} \\ \\ \boxed{\boxed{a=12}} \\ \\ \\ \\ Therefore,\ the\ height\ or\ the\ adjacent\ side\ (a)\ is\ equal\ to\ \bold{12} \\ \\ \\ Hope\ it\ Helps:) [/tex]
