Answer:
1) OE = 30cm 3) ∠1 = 52° 5) ∠1 = 45°, ∠2 = 45°, ∠3 = 90°
2) EM = 12.5cm 4) BS = 24cm
Step-by-step explanation:
1) - 3)
Since the given figure is a rectangle the diagonal are equal length
If LV = 30, OE = 30cm
EO = 25cm, EM [tex]\frac{25}{2}[/tex] = 12.5cm
m∠2 = 38° ∠1 = 90 - 38
= 52°
4) BO = 12 cm
BS = 12 + 12 = 24cm
Since AE bisects line BS,
BO = OS = 12
BS = BO + OS
BS = 12 + 12 = 24cm
5) If m∠OBE = 45°
m∠OBA is also 45°
Since OS bisects angle ABE
m∠OBE = m∠OBA = 45°
m∠BOA = 90°
since BS ⊥ AE
∠OAB = 180 - (90 + 45)
= 45°
∠1 = 45°, ∠2 = 45°, ∠3 = 90°