1. Show all the possible outcomes using tree diagram.=
Answer:
All probabilities add to 1.0 (which is always a good check)
The probability of getting at least one head from two tosses is 0.25+0.25-0.25-0.75
2.What is the probability of tossing:
a. three heads?
b. two heads and a tail?
c. at least one head?
d. no heads?
3. Determine the odds in favor of getting two tails and a head.
Assume the coins are unbiased. There are [math]2×2×2=2^3=8[/math] possible outcomes. They are: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.
Getting two tails and one head are the [math]3[/math] events HTT, THT, TTH. Not getting exactly two tails and one head are the remaining [math]5[/math] events.
Odds in favor are the number of favorable outcomes to the number of unfavorable outcomes. (See Math Only Math | Learn math step-by-step. for more about odds in probability.)
So, the odds in favor of getting exactly [math]2[/math] tails and [math]1[/math] head are [math]3[/math] to [math]5[/math].
I hope it helps
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