Grade 10 Mathematics
SITUATION: Before the COVID-19 crisis, our school offers 2 types of Filipino food for snacks (Banana Turon and Rice Muron), 3 types of drinks (Lemon Juice, Orange Juice, and Iced Tea), and 2 types of fruits (Banana and Apple). How many different snacks can be chosen consisting of 1 snack, 1 drink, and 1 fruit can be made? (LIST DOWN THE POSSIBLE OUTCOMES)

(REMINDER: It would be very great if someone could give a reliable and precise answer. Your help is very much needed. Thank you in advance.)

Before the COVID-19 crisis, our school offers 2 types of Filipino food for snacks (Banana Turon and Rice Muron), 3 types of drinks (Lemon Juice, Orange Juice, and Iced Tea), and 2 types of fruits (Banana and Apple). How many different snacks can be chosen consisting of 1 snack, 1 drink, and 1 fruit can be made?

SOLUTION:

Let's look at the 2 snacks and 3 drinks first and then expand the calculation. There are 6 ways I can have one of the snacks and 1 of the drinks:

Snack 1 Snack 2

⎛Drink 1 1 2

⎜

⎜Drink 2 3 4

⎜

⎜Drink 3 5 6

⎝

And so we can see that we multiply the number of snacks and the number of drinks to get the total number of ways to get one of each.

The same works for more categories of choices, and so we multiply the 2 snacks, 3 drinks, and 2 fruits:

2 × 3 × 2 = 12

Therefore, there are 12 different snacks we can choose consisting of 1 snack, 1 drink, and 1 fruit.

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