Answer:
ANSWER = Let us name event A as the event of drawing a spade and let us name event B as the event of drawing an ace
Now, we are required to find P(A union B)
We know that P(A union B) = P(A) + P(B) - P(A
intersection B) ... (i)
We have P(A) = 13/52 = 1/4 and P(B) = 4/52 = 1/13. A intersection B denotes the case of the ace of spade whose probability = 1/52. Now plugging in these values to equation (i) and simplifying, we obtain the required probability as 4/13
