[tex]\tt{\huge{\red{Solution:}}}[/tex]
Based on the balanced chemical equation, 7 moles of O₂ is stoichiometrically equivalent to 4 moles of CO₂. Note that the molar mass of O₂ is 32 g/mol.
[tex]\begin{aligned} \text{moles of} \: \text{CO}_2 & = 32 \: \cancel{\text{g} \: \text{O}_2} \times \frac{1 \: \cancel{\text{mol} \: \text{O}_2}}{32 \: \cancel{\text{g} \: \text{O}_2}} \times \frac{\text{4 mol} \: \text{CO}_2}{7 \: \cancel{\text{mol} \: \text{O}_2}} \\ & = \boxed{\text{0.57 mol} \: \text{CO}_2} \end{aligned}[/tex]
Hence, 0.57 mol of CO₂ will be produced using 32 g of O₂.
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