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"Ms. Santos asked Renz to draw all the diagonals of a certain polygon on the blackboard. Renz was able to draw 27 diagonals which his teacher declared correct. What was the given polygon?
a. pentagon
c. nonagon
b. hexagon
d. decagon "

Sagot :

Answer: Nonagon

Number of Diagonals = n(n-3)
                                       2

n = number of sides
27 = given number of diagonals

27 = n(n-3)
          2

27 = n² - 3n
          2

(2) 27 = n² - 3n
54 = n² - 3n

Write as quadratic equation in the form ax² + bx + c = 0

n² - 3n = 54
n² - 3n - 54 =0

Solve by factoring:
(n - 9) (n + 6) = 0

n - 9 = 0             n + 6 = 0
n = 9                  n = -6

Choose the possible solution (root), n = 9

The polygon is a nonagon because it has 9 sides.

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