What is the quotient of (6x^4+6x^3+x^2+x-3), (x-1)?


Sagot :

You can answer it easily by just using synthetic division.

The answer is:

Q(x) = 6x^3 + 12x^2 +13x + 14 and the remainder is 11.

It could be like this:

Q(x) = 6x^3 + 12x^2 + 13x + 14 + 11/x-1

Synthetic division:
(1)   6       6        1      1      -3
               6        12    13     14
=     6      12      13     14     11
     x^3     x^2      x      c      r