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3Methanol (CH₃OH) burns in air according to the equation. 2CH₂OH + 302 - 2 CO2 + 4H₂O , If 209 g of methanol are used up in a combustion process, what is the mass H₂O produced?​

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Answer:

Answer:Methanol burns in air to form carbon dioxide and water: 2 CH3OH + 3 O2 ---> 2 CO2 + 4 H2O If 209 g of CH3OH are used up, what mass of H2O is produced? The answer is = 235 g H2O.

Answer:Methanol burns in air to form carbon dioxide and water: 2 CH3OH + 3 O2 ---> 2 CO2 + 4 H2O If 209 g of CH3OH are used up, what mass of H2O is produced? The answer is = 235 g H2O.Explanation:

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