Answer:
D
Solution:
[tex]\frac{e-5}{e-3}[/tex] = [tex]\frac{e+3}{20}[/tex]
e-5 = [tex]\frac{(e+3)(e-3)}{20}[/tex]
e-5 = [tex]\frac{e^{2}-9}{20}[/tex]
20e - 100 = [tex]e^{2}[/tex] - 9
[tex]-e^{2}[/tex] + 20e - 91 = 0
[tex]e^{2}[/tex] - 20e + 91 = 0
(e - 13)(e - 7) = 0
e = 13, 7
