Problem:
The sum of two numbers is 15. One less than three time the smaller is equal to the larger?
Solution:
Let x be the first number
Then let 3x - 1 be the second number
In representation:
The sum of two numbers is 15
- (1st) + (2nd) = 15
- x + (3x - 1) = 15
Solve the value of x which is the first number to the problem equations.
- x + (3x - 1) = 15
- 4x - 1 = 15
- 4x = 15 + 1
- 4x = 16/4
- x = 4
Substitute the second number to the first number which is the value of x to the solving the problem equation.
- 2nd = 3x - 1
- 2nd = 3(4) - 1
- 2nd = 12 - 1
- 2nd = 11
Checking:
Checking the first number and second number if the answer is correct.
- (1st) + (2nd) = 15
- x + (3x - 1) = 15
- (4) + (3(4) - 1) = 15
- 4 + (12 - 1) = 15
- 4 + 11 = 15
- 15 = 15 ✔
Answer:
∴ Therefore, the first number is 4 and the second number is 11 to the sum of two numbers is 15.
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