Sagot :
MATH
[tex]\huge\mathtt{✒Solution:}[/tex]
[tex]•••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \mathtt{ \frac{4}{5} + \frac{1}{5} }[/tex]
Find common denominator and write the numerators above common denominator
[tex] \mathtt{ \frac{4 \times 4}{5 \times 4} + \frac{5}{4 \times 5} }[/tex]
[tex] \mathtt{ = \frac{16}{20} + \frac{5}{20} }[/tex]
[tex] \mathtt{ = \frac{16 + 5}{20} }[/tex]
[tex] = \boxed{\frac{21}{20}}[/tex]
[tex]•••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex]\huge\mathtt{✒Answer:}[/tex]
[tex]•••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
Therefore the answer is 21/20
[tex]•••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
(/^_^)/
4/5 + 1/4 = ?
Solution:
4/5 1/4
5 × 4
= 20
...... + .....
20 20
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4 1
5 4 , multiply 4 by the denominator of 1 which is 4,then multiply 1 by the denominator of 4 which is 5.
4×4=16
1×5=5
=
16 + 5
20 20
16+5= 21
= 21
20
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Can we reduce 21/20?
The answer is no,because the GCF (Greatest Common Factor) of 21 and 20 is 1,we divide 1 to 21 and 20 the answer will be 21
20.
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Therefore the answer is 21/20.
Note: I didnt copy the answer of the person who answered this question first.
Hope it helps and I hope that your kind enough to make me brainliest :(