Sagot :
Explanation:
The equation of straight line passing through the given points
(x1, y1) = (4, 7) & (x2, y2) = (−2, 6) is given by following formula
answer:
y-y1 = y2-y1/x2-x1 (x-x1) y-7= 6-7/-2-4 (x-4) y-7=1/6 (x-4) 6y-42=x-4 x-6y+38=0
Answer:
[tex]y = \frac{1 }{6} \times + \frac{19}{3}[/tex]
sana makatulong :)