Answer:
For this question Atomic Mass of Carbon C = 12 g/mol, Hydrogen H = 1 g/mol and oxygen O = 16 g/mol.
The Molecular Mass of the compound is 60 g/mole so you have to find the Mass of each element from its percentage as follows:
Carbon 40% of 60 g/mol = 40/100 x 60 = 24 g we divide this by the Atomic Mass of Carbon which is 12 so 24/12 = 2 Carbon atoms in the compound.
Hydrogen 6.5% of 60 g/m = 6.5/100 x 60 = 3.9 g we divide this by the atomic Mass of Hydrogen which is 1 so 3.9/1 = 4 atoms of H in the Compound.
Finally Oxygen 53.5% of 60 g/mol = 53.5/100 x 60 = 32.1 g we divide by the atomic Mass of Oxygen which is 16 so 32.1/16 = 2 atoms of oxygen in the compound.
So we have 2 Carbons, 4 Hydrogens and 2 Oxygen so the Molecular formula of the Compound is C2H4O2
Answer: Molecular Formula of the Compound = C2H4O2
