What is the roots of x3-6x2+11x-6=0

Sagot :

From the rational root theorem, actor out x-1 from x³ - 6x² + 11x -6 = 0:

(x-1) (x²-5x+6)

Factor further (x²-5x+6): (x - 3) (x-2)

The factors of the polynomial:
(x-1) (x-3) (x-2) = 0

x - 1 = 0             x - 3 = 0            x - 2 = 0
x = 1                 x = 3                  x = 2

The roots are:  1, 2, 3