8x + 10-7X = 6x + 12
EQUATION​


Sagot :

✒️[tex]\large{\mathcal{ANSWER}}[/tex]

[tex]======================[/tex]

  • The correct value of x that satisfies this equation of the first degree is -0.4 .

To solve this equation, let's subtract the similar terms before the equality. Then let's move 6x to the other side of the negative equality:

[tex]8x + 10 - 7x = 6x + 12[/tex]

[tex]8x - 7x + 10 = 6x + 12[/tex]

[tex]x + 10 = 6x + 12[/tex]

[tex]x + 10 - 6x = 12[/tex]

Now, let's subtract the equal terms from this equation on both sides. Let's move +10 to the other side of the equation by subtracting.

[tex]x + 10 - 6x = 12[/tex]

[tex]x - 6x = 12 - 10[/tex]

[tex] - 5x = 2[/tex]

Finally , we will isolate x and we will divide these terms among themselves :

[tex] - 5x = 2[/tex]

[tex]x = 2 - 5[/tex]

[tex] \: \boxed{x = -0,4} √[/tex]

[tex]−−−−−−−✠−−−−−−−[/tex]