2 -3° + (-6 x 2) + 5 - 12 The result of this numerical expression is...
(If possible, show step-by-step).​


Sagot :

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The value of your numeric expression will be equal to - 33. As we already know, numeric expressions are mathematical calculations, calculated according to their rules, which are: Elimination rule, and operation, finally, the sign, See below:

  • Elimination rule:
  • Parentheses >> ().
  • Brackets >> [].
  • Braces >> {}.

And soon, we see the other little rule, which is also super !

See below:

  • Operation rule:
  • Potentiation >> x².
  • Multiplication and division >> x/÷.
  • Addition and subtraction >> +/-.

And finally, our sign,

See below:

  • (+) x ( + ) = ( + ).
  • (-) × (-) = (+).
  • (+) × ( - ) = ( - ).
  • (-) x (+) = (-).

So, we already know how to calculate;

Let's go to your exercise... 2-33 + 6 x 2) + 5 - 12, we solve the potentiation, getting: 33 = 27, then we multiply, ( - 6 x 2) = (-12). Any potentiation that is based on the number 1 will be equal to 1. Therefore, 12 = 1. We remove the positive sign in front of (-12). We add 5 to 7, then 27 to 12 and 1, getting 40, and finally we subtract, 7 - 40, which gives - 33.

See the full calculation below:

[tex]2 - {3}^{3} + ( - 6 \times 2) + 5 - {1}^{2} \\ 2 - 27 + ( - 6 \times 2) + 5 - {1}^{2} \\ 2 - 27 + ( - 12) + 5 - {1}^{2} \\ 2 - 27 + ( - 12) + 5 - 1 \\ 2 - 27 - 12 - 1 \\ 7 - 27 - 12 - 1 \\ 7 - 39 + 5 - 1 \\ 7 - 40 \\ \: \boxed{=-33} [/tex]

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