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1.) Evaluate 3x + 5 when x = 2
2.) Evaluate 6x - 2y when x =3 and y = 2
3.) Evaluate 3x² + 2x - 5 when x = 2​

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ANSWER

1.) Evaluate 3x + 5 when x = 2

We replace x by 2, we have

  • 3 (2) + 5

Perform the indicated operation by;

  • [tex]\large3(2) + 5 \: \: {\longrightarrow} \: \: {\small{\green{\rm{multiplication \: first}}}}[/tex]
  • [tex]\large6 + 5 \: {\longrightarrow} \: {\small{\blue{\rm{addition \: second}}}}[/tex]

So when x = 2, 3x + 5 is equal to 11

Answer: [tex]\large{\boxed{11}}[/tex]

2.) Evaluate 6x - 2y when x =3 and y = 2

We replace x by 3 and y by 2

  • [tex]6(3) - 2(2)[/tex]
  • [tex]18 - 4[/tex]
  • [tex] = 14[/tex]

Therefore when x = 3 and y = 2, 6x - 2y is equal to 14

Answer: [tex]\large{\boxed{14}}[/tex]

3.) Evaluate 3x² + 2x - 5 when x = 2

SOLUTION;

  • [tex] \tt \: {3x}^{2} + 2x - 5[/tex]
  • [tex]\tt \: = 3(2 {)}^{2} + 2(2) - 5[/tex]
  • [tex] = 3(4) + 2(2) - 5[/tex]
  • [tex] = 12 + 4 - 5[/tex]
  • [tex] = 11[/tex]

Substitute x as 2

Evaluate the power first, then, multiply

Add and subtract

Answer: [tex]\large{\boxed{11}}[/tex]]

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