[tex]\large\underline\mathcal{SOLUTION:}[/tex]
Given rectangle, with:
- Perimeter, P = 30 units
- length, l = 3 + √x units
- width, w = √x units
then,
- P = 2 (l + w)
- 30 = 2 (3 + √x + √x)
- 30 = 2 (3 + 2√x)
- 30 = 6 + 4√x
- 4√x = 30 - 6
- √x = 24/4
- (√x)² = (6)²
- x = 36
We get, Solve for length:
- l = 3 +√x
- l = 3 + √36
- l = 3 + 6
- l = [tex]{\boxed{\green{\sf{9\:units }}}}[/tex]
Solve for width,
- w = √x
- w = √36
- w = [tex]{\boxed{\green{\sf{6\:units }}}}[/tex]
[tex]\large\underline\mathcal{ANSWER:}[/tex]
- Therefore, the length of the rectangle is 9 units and the width is 6 units.
hope this helps
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