SOLVE THE PROBLEM :
if p varies directly as q and p=18 when q =-6, then k is...
[tex] \orange{ \bold{p = kq}} \\ 18 = (k)( - 6) \\ k = \tiny \frac{18}{ - 6} \\ k = - 3[/tex]
The constant of variation is k = - 3
[tex] \orange{ \boxed{ \bold{ a.) \: k = - 3}}}[/tex]