what is the quadratic equation by completing the square of r²-10r=-17

Sagot :

r²-10r=-17
r²-10r+25=-17+25
r²-10r+25=8
( r-5 )²=8
r-5 = positive or negative 2√2





[tex] r^{2} -10r = -17
r^{2} -10r +25 = -17 + 25
\boxed{r^{2} -10r +25 = 8}
 (r-5)^{2} = 8 r-5 = ±\sqrt{8} = ±2 \sqrt{2}
\boxed{r= 5 + 2 \sqrt{2} }
\boxed{r= 5- 2 \sqrt{2} }[/tex]

Note: Please disregard the A's.