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the sum of the digits of a two-digit number is 17. Four times the tens digit is 12 more than thrice the ones digit. What is the original number?

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98 is the answer
the sum of the 2 digits is written as
x+y=17,where x is the tens digit and y is the ones digit
4 times the tens wc is 4x is equal to thrice the ones +12
so 4x -3y=12
eliminate 
so (x + y= 17)3
     4x-3y=12

add the equation
you get 7x=63
            x=9
x+y =17
9+y=17
y=8
the number is 98


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