Answer:
5,15
Explanation:
The equation of the given circle is x2+y2−4x−2y−20=0 and when substituted x=10 & y=7, its value becomes 100+49−40−14−20=75 which is greater than zero.
Thus, the point (10,7) lies outside the circle.
Its distance from the centre of the circle (2,1) is (10−2)2+(7−1)2=100=10 unit.
The minimum distance from the circle therefore becomes 10−5(i.e. radius) =5 and the maximum distance becomes 10+5=15 unit.
