Answered

What is the 10th term of arithmetic sequence 5, 12, 19, 26 ...?

Sagot :

AGboiiviz

[tex]\large{\mathcal{SOLUTION:}}[/tex]

Using the arithmetic sequence formula:

  • [tex]\rm{S_n=A_1+(n-1)d}[/tex]

[tex] \\ [/tex]

Given:

  • n = 10
  • [tex]A_1=10[/tex]
  • D = ?

[tex] \\ [/tex]

STEP 1: Find the common difference.

  • D = Succeding tem - Preceding term
  • D = 12 - 5
  • D = 7

[tex] \\ [/tex]

STEP 2: Find for the 10th term

  • [tex]\rm{S_n=A_1+(n-1)d}[/tex]

  • [tex]\rm{S_{10}=10+(10-1)7}[/tex]

  • [tex]\rm{S_{10}=10+(9)7}[/tex]

  • [tex]\rm{S_{10}=10+63}[/tex]

  • [tex]\rm{S_{10}=73}[/tex]

Therefore , the tenth term is 73

[tex] \\ [/tex]

[tex]\large{\mathcal{ANSWER:}}[/tex]

  • 73

[tex] \\ [/tex]

LoveArtemis18viz

Answer:

The answer of arithmetic sequence in 10th term was 68

Step-by-step explanation:

So the first term was 5 when you add 7 it's equal to 12 and 12 was the second term when you add 7 again the answer was 19 and add 7 again and so on.

5+7=12

12+7=19

19+7=26

26+7=33

33+7=40

40+7=47

47+7=54

54+7=61

61+7=68