please help my question about this​

Please Help My Question About This class=

Sagot :

Answer:

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[tex]\huge \tt{ANSWERS:}[/tex]

[tex]1) \: \: \frac{8}{11} [/tex]

[tex]2) \: \: \frac{5}{8} [/tex]

[tex]3) \: \: \frac{1}{2} [/tex]

[tex]4) \: \: \frac{8}{15} [/tex]

[tex]5) \: \: 1\frac{1}{8} [/tex]

[tex]\red{⊱┈────────────────────┈⊰}[/tex]

[tex]\huge \tt{SOLUTIONS:}[/tex]

1)

[tex] \frac{5}{11} + \frac{3}{11} = \frac{5 + 3}{11} = \frac{8}{11} [/tex]

2)

[tex] \frac{7}{8} - \frac{4}{16} = \frac{7}{8} - \frac{1}{4} = \frac{7 - 2 \times 1}{8} = \frac{5}{8} [/tex]

3)

[tex] \frac{5}{12} \times \frac{6}{5} = \frac{5 \times 6}{12 \times 5} = \frac{30}{60} = \frac{1}{2} [/tex]

4)

[tex] \frac{4}{15} \div \frac{6}{12} = \frac{4}{15} \div \frac{1}{2} = \frac{4 \times 2}{15 \times 1} = \frac{8}{15}[/tex]

( at the no.5,we have 3 solutions )

5)

FIRST,

[tex] \frac{4}{6} + \frac{1}{3} = \frac{2}{3} + \frac{1}{3} = \frac{2 + 1}{3} = \frac{3}{3} = 1[/tex]

THEN,

[tex] \frac{2}{4} + \frac{5}{8} = \frac{1}{2} + \frac{5}{8} = \frac{4 \times 1 + 5}{8} = \frac{9}{8} = 1 \frac{1}{8} [/tex]

LASTLY

[tex]1 \times 1 \frac{1}{8} = \frac{9}{8} = 1 \frac{1}{8} [/tex]

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