Answer:
1.
3x² + 2x – 1=03x²+2x–1=0
Here, we can apply quadratic formula
x = \frac{−b± \sqrt{b^2−4ac} }{2a}x=
2a
−b±
b
2
−4ac
Where a = 3, b = 2, c = -1
Plugging these into the equation, we have;
x = \frac{−2± \sqrt{2^2−(4×3×-1)} }{2×-1}x=
2×−1
−2±
2
2
−(4×3×−1)
