Sagot :
3(x+2)² = 2x² +3x -8
3(x²+4x+4) = 2x² +3x -8
3x² +12x +12 -2x² -3x +8 = 0
x² +9x +20 = 0
(x+4) (x+5) = 0
x=-4 ; x=-5
3(x²+4x+4) = 2x² +3x -8
3x² +12x +12 -2x² -3x +8 = 0
x² +9x +20 = 0
(x+4) (x+5) = 0
x=-4 ; x=-5
Answer:
3(x + 2)^2 = 2x^2 + 3x - 8
3(x^2 + 4x + 4) = 2x^2 + 3x - 8
3x^2 + 12x + 12 = 2x^2 + 3x - 8
3x^2 - 2x^2 + 12x - 3x + 12 + 8 = 0
x^2 + 9x + 20 = 0
(x + 5)(x + 4) = 0
x + 5 = 0
x = -5
x + 4 = 0
x = -4
x = {-5,-4}
Hope it helps kahit na may nauna na sa akin na sumagot. :)
3(x + 2)^2 = 2x^2 + 3x - 8
3(x^2 + 4x + 4) = 2x^2 + 3x - 8
3x^2 + 12x + 12 = 2x^2 + 3x - 8
3x^2 - 2x^2 + 12x - 3x + 12 + 8 = 0
x^2 + 9x + 20 = 0
(x + 5)(x + 4) = 0
x + 5 = 0
x = -5
x + 4 = 0
x = -4
x = {-5,-4}
Hope it helps kahit na may nauna na sa akin na sumagot. :)