Kisseyofficialviz
Answered

The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find these integer.


Show me your soltion please :) BTW OUR TOPIC IS ABOUT QUADRATIC EQUATIONS and solve this using one variable only :)

Sagot :

This is linear.

Let the first odd integer = x
            second odd integer = X + 2
            third odd integer = x+4

(x) (x + 2) = (x + 4)² - 58
x² + 2x = x² + 8x + 16 - 58
x² - x² + 2x - 8x - 16 + 58 = 0

-6x + 42 = 0       (linear equation)

-6x = -42
-6       -6
   x = 7

Substitute 7 for x

First odd integer:  x = 7
Second odd integer: x + 2 
                                      7 + 2 
                                       = 9

third odd integer: x + 4 
                               7 + 4
                               = 11

The three consecutive odd integers are 7, 9, 11