the sum of two numbers is 86 and their difference is 22. Find the numbers


Sagot :

It is 54 and 32
54 + 32 = 86
54 - 32 = 22

solution:
a + b = 86
a  - b = 22          add the two numbers
2a     = 108

by multiplication property of equality, divide it to two to cancel out 2a to only a
a = 54

therefore the one digit is 54
54 + b  = 86
86 - 54 = b
86 - 54 = 32

therefore the digits are 54 and 32

54 + 32 = 86
54 - 32 = 22