find the geometric series of each infinite geometric sequence. 12, 6, 3, …S7with solution please pa help​

Sagot :

Answer:

S7 = 3/16 "oum fraction po talaga yung sagot cinonvert ko langs yung decimal"

Step-by-step explanation:

Given:

n=7 a1=12 a2=6 a3=3

r= a2÷a1

= 6÷12

=1/2

Solution:

an=a1 r^n-1

a7=12 (1/2)^7-1

a7=12 (1/2)^6

a7=12 (1/64)

a7= 3/16

Hope it helps..<3

Answer:

Sn=a1 ( 1-rn) / 1-r

Sn= 12 (1-(.57) / 1-0.5

Sn= 12 (1- 0.0078125) 2

Sn = 12 (0.9921875) 2

Sn = (11.90625) 2

Sn = 23.8125

Checking

12 + 6 + 3 + 1.5 + 0.75 + 0.375 + 0.1875 = 23.8125

Paalala: 5 to the power of 7 yung pag substitute sa r to the power of n