solving quadratic equation by extracting the square root
2x^2 +5= -7x


Sagot :

[tex]\pink{2x²+7x+5=0}\\x = \frac{ - ( 7)\sqrt[ + - ]{ - ( 7 ){}^{2} - 4 \times 2 \times 5 } }{2 \times 2} \\ x = \frac{-7 \sqrt[ + - ]{49 - 40} }{4} \\ x = \frac{-7 \sqrt[ + - ]{9} }{4} \\ x = \frac{-7 + 3 }{4} \\ and \\ x = \frac{-7 - 3}{4} \\\\\gray{\underline {\large \bold{A}}} \green{\underline { \large \bold {N}}} \red{\underline { \large \bold {S}}} \orange{\underline { \large \bold {W}}} \blue{\underline { \large \bold {E}}} \pink{\underline { \large \bold {R}}}\\\\ roots \: are : \\ x = \frac{-5}{2} \: and \: x = -1 \\ \boxed{\red{by \: jai}}[/tex]