express f (x) = 3(x-7)² +5 in the form f (x) =ax²+bx+c​

Sagot :

Answer:

147+5fx

3

a+bx+c

Step-by-step explanation:

1 Since the power of 2 is even, the result will be positive.

3\times {7}^{2}+5fxa{x}^{2}+bx+c

3×7

2

+5fxax

2

+bx+c

2 Simplify {7}^{2}7

2

to 4949.

3\times 49+5fxa{x}^{2}+bx+c

3×49+5fxax

2

+bx+c

3 Simplify 3\times 493×49 to 147147.

147+5fxa{x}^{2}+bx+c

147+5fxax

2

+bx+c

4 Regroup terms.

147+5fx{x}^{2}a+bx+c

147+5fxx

2

a+bx+c

5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

147+5f{x}^{1+2}a+bx+c

147+5fx

1+2

a+bx+c

6 Simplify 1+21+2 to 33.

147+5f{x}^{3}a+bx+c

147+5fx

3

a+bx+c