1.The sum of two numbers is 10.The larger number is 8 more than the smaller number. Find the two numbers?

Solution:









Answer:


2.The sum of Janna age and Mark's age is 40.Two years ago, Janna was twice as old as Mark.Find Janna's age?

Solution:








Answer:​


Sagot :

Answer:

1.

let the larger number = x+8

let the smaller number = x

(x+8)+(x)=10

x+8+x=10

2x+8=10 (combine like terms)

2x=10-8

2x=2 (divide both sides by 2)

x=1

larger number = x+8

1+8=9

smaller number = x

1

therefore, the larger number is 9 while the other number is 1.

2.

2yrs ago

janna - 2x

mark - x

today

janna - 2x+2

mark - x+2

(2x+2)+(x+2)=40

3x+4=40

3x=36 (divide both sides by 3)

x=12

janna's age

2x+2

2(12)+2

24+2=26

therefore, janna's age is 26.