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Demincal ÷10 ÷100 ÷10001.)3.8142.)148.233.)2354.3534.)28.25.)143.0462.)148.233.)2354.3534.)28.25.)143.046

Sagot :

Ymir21viz

Answer:

• The minimum point exists if a>0. It is (h, k). So h=2, k=5

If y=a(x-2.5)^2+5 passes through (1,9) we have

9=a(1–2.5)^2+5.

From this we find a.

Step-by-step explanation:

• gt lss