find the first four terms of the sequence an = 3n -2?

a)1,4,7,10
b)3,7,11,15
c) 5,9,13,17
d) 6,11,16,21​


Sagot :

✏️SEQUENCE

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[tex]\large\bold{\red{QUESTION:}}[/tex] Find the first four terms of the sequence: [tex]\sf{a_n = 3n - 2}[/tex]?

[tex]\large\bold{\red{ANSWER:}} \: \large\underline{\sf{\green{\:\:A. \: 1,4,7,10 \: \:}}} [/tex]

- Solve the first four terms of the sequence. Then find the common difference of these terms.

[tex]\large\sf{a_1}[/tex]

  • [tex]\sf{a_n = 3n - 2}[/tex]

  • [tex]\sf{a_1 = 3(1) - 2}[/tex]

  • [tex]\sf{a_1 = 3 - 2}[/tex]

  • [tex]\sf{a_1 = 1}[/tex]

[tex] \large \sf[/tex]

[tex]\large\sf{a_2}[/tex]

  • [tex]\sf{a_n = 3n - 2}[/tex]

  • [tex]\sf{a_2 = 3(2) - 2}[/tex]

  • [tex]\sf{a_2 = 6 - 2}[/tex]

  • [tex]\sf{a_2 = 4}[/tex]

[tex] \large \sf[/tex]

[tex]\large\sf{a_3}[/tex]

  • [tex]\sf{a_n = 3n - 2}[/tex]

  • [tex]\sf{a_3 = 3(3) - 2}[/tex]

  • [tex]\sf{a_3 = 9 - 2}[/tex]

  • [tex]\sf{a_3 = 7}[/tex]

[tex] \large \sf[/tex]

[tex]\large\sf{a_4}[/tex]

  • [tex]\sf{a_n = 3n - 2}[/tex]

  • [tex]\sf{a_4 = 3(4) - 2}[/tex]

  • [tex]\sf{a_4 = 12 - 2}[/tex]

  • [tex]\sf{a_4 = 10}[/tex]

- Therefore, the common difference is 3

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