Answered

If the light bulb is elevated at 3.2 m from the ground and has a mass of 0.3 kg, what is the potential energy of the bulb?​

Sagot :

Answer:

the potential energy of the bulb is 9.41 J.

Explanation:

h = 3.2 m

m = 0.3 kg

PE = mgh

PE = (0.3 kg)(9.8 m/s²)(3.2 m)

PE = 9.408 kg • m²/s²

PE = 9.41 kg•m²/s²

PE = 9.41 J

Viz Other Questions