FORMULA:
[tex]d = r \times t[/tex]
where d = distance, r = rate, and t = time
SOLUTION:
First, we need to find the rate. Thus,
[tex] d_{1} = r \times t_{1} \\ 30 = r \times 90 \\ \: \: \: \: \: r = \frac{30}{90} = \frac{1}{3} [/tex]
We can now solve for the time it takes to run a distance of 67 kms. That is,
[tex] d_{2} = \frac{1}{3} \times t_{2} \\ 67 = \frac{1}{3} \times t_{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: t_{2} = 67 \times 3 = 201[/tex]
ANSWER:
Therefore, it only takes [tex]\green{\boxed{201 \: minutes}}[/tex]
for Scott to run in a 67 km distance.
