Learning Task 3. Find the largest area which the farmer can enclose with 56 m of fencing materials.

Step-by-step explanation:
A=(28-n)n
dA/dn =0
(28-n)(1)+(n)(-1)=0
28-n-n=0
28=2n
n=28/2=14
A=(28 -14) 14
A=14×14
A=196m^2
ANSWER:196m^2
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